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center and radius of a circle?

how do i find center and radius of this ?

x^2 + y^2 + 16x + 10y = 85

8 Answers

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  • 1 decade ago
    Favorite Answer

    Factor x and y separately by completing the square:

    (x² + 16x) + (y² + 10y) = 85

    (x² + 16x + 64) + (y² + 10y + 25) = 85 + 64 + 25

    (x + 8)² + (y + 5)² = 174

    The center is at (-8, -5) and the radius is about 13.19 units.

  • 1 decade ago

    Complete the squares:

    x^2 +16x +64 +y^2 +10y +25 = 85+ 64+25

    (x+8)^2 + (y+5)^2 = 174

    So center is at (-8, -5) and radius = sqrt(174)

  • 1 decade ago

    You need to complete the square. First rewrite the equation as x^2+16x+64+y^2+10y+25=85+64+25, which reduces to (x+8)^2+(y+5)^2=174. With the equation in this format, you can see that the center of the cirle is (-8,-5), with radius sqrt (174).

    Source(s): algebra
  • iluxa
    Lv 5
    1 decade ago

    remember the circle equation:

    (x - Cx)^2 + (y-Cy)^2 = R^2,

    where Cx, Cy is the center, and R is the radius

    so you have to convert your equation into something looking like that.

    you have

    x^2 + 16x, would be nice to have x^2+16x+64, since that's (x+8)^2

    likewise, y^2+10y better be y^2+10y+25 = (y+5)^2

    so

    x^2 + y^2 + 16x + 10y = 85

    x^2 + y^2 + 16x + 10y + 64 + 25 = 85 + 64 + 25

    (x+8)^2 + (y+5)^2 = 174

    so there you have it. The circle is centered at (-8, -5), and its radius is sqrt (174)

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  • 1 decade ago

    complete square for x and y

    to bring it in the standard circle eq. form:

    x^2+16x+8^2-8^2 +y^2+10y+5^2-5^2=85

    (x+8)^2+(y+5)^2=174

    centre= (-8,-5)

    radius=√174

  • Anonymous
    4 years ago

    X*2+Y*2-10X+2Y+25=0 you ought to get in the format (x+a)^2 + (y+b)^2 = c a and b would properly be ant huge style; c must be constructive regroup (x^2 -10x + 25) + (y^2 + 2y) = 0 upload a million to the two sides to end the sq. (x^2 -10x +25) + (y^2 +2y +a million) = a million (x-5)^2 + (y+a million)^2 = a million center = 5, -a million you get that via fixing (x-5) = 0 x = 5 (y+a million) = 0 y = -a million radius = sqrt of the c term radius =sqrt(c) = sqrt(a million) r = a million

  • 1 decade ago

    Complete the squares in x and y

    For a circle of radius r and centre (x0 , y0) the equation is

    (x - x0)^2 + (y -y0)^2 = r^2 ==> x^2 -2x0x +x0^2 + y^2 -2y0y +y0^2 = r^2 ==> x^2 -2x0x + y^2 -2y0y = r^2 + x0^2 + y0^2

    And your centre is by comparison x0 = -16/2 = -8 and y0 = -10/2 = -5 ie C: (-8 , -5)

  • 1 decade ago

    =>x^2+2*8*x+64+y^2+2*5*y+25=85+64+25

    =>(x+8)^2+(y+5)^2=174

    center is(-8,-5)

    radius=sqrt174

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