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Molecular weight, acid titration?
In my lab, we have to figure out the molecular weight of an unknown diprotic acid.
Using a .082 Molar NaOH base, the first equivalence point was at 12.86 mL and the second equivalence point was at 26.81mL of NaOH, from this I have calculated that the moles of NaOH were .0044 so thus the moles of the unknown acid is .004 (at the second equivalence point)
Does anyone know how to go about finding the weight of the acid?
1 Answer
- helloLv 41 decade agoFavorite Answer
molar mass = mass*# of moles
you can find the # of moles =concentration *volume in liter
i think this is the way to do it, hope it's right
