help on factoring polynomials?

Let's use x3 to mean x cubed.

So,

-x3 + 16 x2 - 60x = (factor out x)

x( -x2+16x -60) = (factor out minus sign)

-x( x2-16x + 60) =

-x(x-10)(x-6)

You can also write this as:

x(10-x)(x-6) (answer)

First, factor out the -1. So, there is x^3 - 16x^2 + 60x = 0.

Then, factor out the x: x(x^2 + -16x + 60) = 0.

For the first factor, x = 0. For the other two . . .

(x -10) (x - 6) = 0

Because there are two factors equal to zero, one of them has to be 0. Any number times 0 equals 0.

If one factor is 6, then 6-6=0. So, the other can be a number. x-10 = 0. x=10.

If one factor is 10, then the other can be a number other than 0. x-6=0. x=6.

Thus, x=10, 6, and 0. There are three real roots, because it is x^3. The exponent tells how many roots are there.

-x(cubed) + 16x(squared) - 60x =

-x{x(squared) - 16x + 60} =

-x(x-6)(x-10)

ok so first u take out the gcf which is x and then factor. so then you have x + 16 -60. and that's your answer!!! good luck on the rest of your hw!

answer = (x+6)(x+10)

10+6=16

10*6=60