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Algebra question!!!!?
In a sport league of n team in which each team plays every other team twice, the total number N of games to be played is given by N=n^2 - n. How many teams are in a softball league if the total number of games played is 182?
Please help!!!
I need the procedure, please!!
6 Answers
- 1 decade agoFavorite Answer
The equation becomes 182 = n^2 - n, which is a quadratic equation. There are many ways to solve this, such as using the quadratic formula, etc. Here, a solution is done using the method of completing the squares:
The equation becomes
n^2 - n = 182. We need to find a number to be added to the left hand side so that it becomes a perfect square. To do that, get the coefficient of n, which is 1. Then divide it by the coefficient of n^2 (which is also 1), then divide it by the constant 2, so that is becomes 1/2. Finally, take its square, which is 1/4. That is the number that you add for each side. The equation then becomes
n^2 - n + 1/4 = 182 + 1/4 = 728/4 + 1/4
=> (n - 1/2)^2 = 729/4
=> n - 1/2 = sqrt(729/4) = +/- 27/2
=> n = 27/2 + 1/2 or n = -27/2 + 1/2
=> n = 14 or -13
Looking back at the problem, we notice that -13 is not a solution. Therefore, the answer is n = 14.
- 1 decade ago
N = 182 =>
182 = n^2 - n =>
n^2 - n -182 = 0
D = 1 + 4*1*182 = 729
n1,2 = (1 +/- 27) /2 =>
n1= 14
n2=-13
=> n=14 (number of teams)
- 1 decade ago
N = n^2 - n
182 = n^2 - n
Algebra
n^2 - n - 182 = 0
(n - 14)(n + 13) = 0
n = 14 or n = -13
Since we are working with teams > 0
n = 14
14 Teams it is!!!
Source(s): My brain!!! :-) - falzoonLv 71 decade ago
n^2 - n = 182
n^2 - n - 182 = 0
(n - 14)(n + 13) = 0
n = 14 or n = -13
Number of teams can't be negative, so n = 14.
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- Anonymous1 decade ago
45.5