Balancing Chemical Equations?

fe203 + 3CO--> 2Fe + 3CO2

and no youre not stupid, it is difficult

This is what I got...

Note: (#) = Subscript.

Before / After, so you can see the change.

Fe(2)O(3) + CO --> Fe + CO(2)

Fe(2)O(3) + 3CO --> 2Fe + 3CO(2)

Totals: 2Fe, 6O, 3C | 2Fe 6O, 3C

Edit: As for the other people bringing in electrons; thats not required when you're doing the simple balancing. Its like math, and finding the lowest common denominator.

Fe2O3 + 3CO--------> 2Fe + 3CO2

Fe changes from +3 to 0 , but they are two Fe then gains 6 electrons.

C changes from +2 to +4 loses 2 electrons, then multiply the C compounds by 3 to equalize electrons. and that's all.

this is a redox. i think the best way to do it is to write the half reactions:

Fe(3+) + 3 e- --> Fe

C (+2) --> C (+4) + 2 e-

now multiply the first one by 2 and the second one by 3 to cancel electrons

2Fe (3+) + 3C (2+) --> 2 Fe + 3C (4+)

since Fe2O3 have 2 Fe's ur done.

Fe2O3 + 3CO --> 2Fe + 3CO2

It's actually:

Fe2O3 + 3CO ---> 2Fe + 3CO2

are you sure you wrote it right?

2Fe2O3 + 6CO ----> 4Fe + 6CO2