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JARQUE-BERA TEST: Does Anyone Understand It?
JB = n/6(S^2 + ((K - 3)^2)/4)
If you use Microsoft Excel or Open Office, don't they already calculate Kurtosis with the -3 in mind and, therefore, this part of the equation for the JB Test should simply be (K^2/4) rather than (K-3)^2/4?
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