Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
i really need help with factoring....?
I need help factoring this problem. I just started school again and I don't remember how to factor this, what i have tried hasnt worked and i have looked online for like almost an hour and it has not worked....the equation is...
x^2-xy-20y^2
i really just need step by step on how to solve them, or just how to solve them. thanks
1 Answer
- 1 decade agoFavorite Answer
it's gonna be (x+5y)(x-4y)
first off, you wanna set up your sets :)
so... ( )( )
now you know that x won't have a number in front of it (if it does, you have to figure out what 2 numbers multiplied together equal that number)
so... (x )(x )
and since we're using the FOIL method (First, Outer, Inner, Last), we've already got the F part down. now we need to figure out the outer part. which will obviously be y.
so... (x y)(x y).
now we need to know if they need pluses or minuses. since the last term in the equation is -20y^2, you know that one needs a + and the other a -, because a + times a - equals a -.
so... (x+ y)(x- y)
now we need to figure out what two numbers multipled together will equal 20 and when added together will equal 1. that would be +5 and -4.
so...(x+5y)(x-4y).
and tah-dah!
to check...
(x+5y)(x-4y)
F: x*x= x^2
O: x*-4y= -4xy
I: x*5y= 5xy
L: 5y*-4y= -20y^2
put it all together: x^2-4xy+5xy-20y^2
reduce: x^2+xy-20y^2