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Prove This Wrong...?
x=1
y=1
I'm not going to put the numbers in the equation, I'm just going to use the variables... prove it wrong. :D
x=y
x^2=xy
x^2-y^2 = xy-y^2
(x+y)(x-y)=y(x-y)
(x+y)(x-y) / (x-y) = y(x-y) / (x-y)
(x+y) = y
THEREFORE
1+1 = 1
Any comments? :D
HAHA, Yall are good. :D I kinda figured somewhere in there it would end up being 0, and then the rest would be irrelivant (sp?). But I didn't bother plugging in the numbers all throughout the problem... lol :P
4 Answers
- 1 decade ago
I'm not going to work through the rest of the problem... one because i can't two it starts off wrong. If x =1 and y = 1 and 1x 2 = 2 then 1 x1=1
2 isn't = 1
I'm not a mathematician but i know that much. Unless ^ doesn't mean X then i don't know what to tell you
- 1 decade ago
Yes, first line says that x =y. Another way to write that is x- y = 0. In the next to last line you divided by x-y, which equals 0, and you can't divide by 0.
You were looking for the error, and there it is.
- Anonymous1 decade ago
old stuff (and nonesense)
comment? boring
