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physics-what am i doing wrong?

a car travels three quarters of a lap on a circular track of radius R...

describe the magnitude of the displacement:

d=3(2piR)/4

i know the answer is greater than R but less than 2R, but i don't understand why?

can you also explain algebraically why when R=50m, the displacement is 71m...when i plug 50 in, i get 235m...i think i have lost it!!!!

Update:

thanks steve...that is exactly what i was doing...i figured it out after starring at it forever. i have been doing way too many problems today.

thanks for your answers!

3 Answers

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  • 1 decade ago
    Favorite Answer

    I think our problem is you are missing the question. It is not how far has the car travelled, it is how mh distance is there from where it started, to where you are taking your measurement. To do that, you have to measure the length of the chord from where it begn, to where 3/4 of the track is circled.

    Think of it this way, if he completes the lap, the total displacement is zero

  • Anonymous
    1 decade ago

    The displacement is a vector pointing from the beginning position to the final position.

    So, let's assume your coordinate system is the xy graph from Cartesian geometry.

    Then, your starting position is point (50,0) and the ending position is (0,-50).

    Draw a triangle (right triangle) with both sides equal to 50. Then the hypotenuse is

    h = (50 * 50 + 50 * 50 ) ^ 0.5

    = 71

    hth.

  • Anonymous
    1 decade ago

    you have the wrong equation.

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