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∫1/(x^3-1)dx?
Partial fractions? I have a feeling I have to manipulate it in some way or form, but I can't figure it out. Any help would be appreciated.
1 Answer
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- 1 decade agoFavorite Answer
You can factor the denominator as
x^3 - 1 = (x-1) (x^2 + x + 1)
Next determine the partial fractions decomposition
1 / (x^3-1) = A / (x-1) + ( Bx + C ) / (x^2+x+1)
and then integrate.
If you're still stuck just ask.
Good Luck!
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