Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
I have a 1700 rpm electric motor with a 3 inch pulley and I want to reduce the output to only 150 rpm.?
The thing is, I want to keep the driven pulley to be less than 10 inches in diameter. If I use a second drive train, with another 3 inch pulley, what would the 2 driven pulleys be like?
4 Answers
- gatorbaitLv 71 decade agoFavorite Answer
If you drive a 10" pulley with your 3"x1700 RPM pulley, the RPM of the 10" pulley will be 3/10*1700 = 510 RPM.
Now if you put another 3" pulley on the same shaft as the 10" pulley the RPM of that 3" pulley will also be 510 RPM.
If you now put a 10" pulley on the final driven shaft, and drive that 10" pulley off of the 3"x510 RPM pulley, the speed of that final shaft will be 3/10*510 RPM = 153 RPM.
So, to get down to 153 RPM, you need two 10" dia. pulleys and one more 3" Dia. pulley.
- 7 years ago
I have an electric motor that spins at 1700 RPM. On its shaft is a 1.5 inch pulley. What size pulley do I need on a spinning shaft to make it turn at 40RPM??
- 4 years ago
Your going to could desire to do somewhat math for this one. 1425 rpm's right down to six rpm's is a few intense help. a three" force equipment has a circumference of approximately 9.40 two". The pushed equipment could desire a circumference of 237" or a diameter of 76" (over 6' !) the two that or a complicated set of help gears or pulleys - i've got not got faith the two could teach very sensible for shifting capability.
