Does anyone know how to solve this?

suppose the sold =S

so the remain in A = 156 -S

the remain in B = 72 -S

(156-S)/(72-S)=4/1

156-S =4(72-S) =288 -4S

3S=288-156 =132

S=44

so every shop sold 44 Kg

Let the amount of rice sold by both shops be x kg.

(156-x) / (72-x) = 4/1

156 - x = 4(72-x)

156 -x = 288 - 4x

4x - x = 288 - 156

3x = 132

x = 132/3 = 44

44 kg of rice was sold by each shop.

Let x = kg of rice sold by both.

=> (156 - x) / (72 - x) = 4

=> 156 - x = 288 - 4x

=> 3x = 132

=> x = 44 kg.

Verification:

Shop A will be left with 156 - 44 = 112 kg

Shop B will be left with 72 - 44 = 28 kg

!!2 / 28 = 4.

let x = amount of rice sold

156- x = left rice for shop A

72- x = left rice for shop B

156-x : 72 - x = 4 : 1

4(72 - x) = 1 (156 - x)

288 - 4x = 156 - x

3x = 132

x = 44 kgs

let amount of rice sold be x

(156-x)/(72-x)=4/1

(156-x)=4(72-x)

156-x = 288-4x

3x= 132

x=44

both shops sold 44kg of rice