Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Calculus Help?
Hey gang! I'm totally confused on this calculus question and could use some help. I know that its an indeterminate power and requires use of l'Hopital's, but I'm stuck. The question is to find the limit of the following equation as x--> 0
y= (1-10x)^(1/x)
Thanks for your help!
4 Answers
- MadhukarLv 71 decade agoFavorite Answer
lim (x -> 0) (1-10x)^(1/x)
= lim (x -> 0) (1 - 10x)^[ (-1/10x) * (-10) ]
= e^(-10)
- Anonymous1 decade ago
By L hospital Rule
=limx->0 -10/(-1/x^2)
=lim x->0 10x^2
=0
- 1 decade ago
From a common sense standpoint, I'd say that the limit is 1.
Since 1-10x approaches 1 and 1/x approaches 0 and 1^0 = 1, thats my approach. Nothing fancy here.
