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Will someone explain this Physics problem to me?
for some reason I think it will remain the same. Am I wrong? Will someone explain? It would realy be appreciated!
a proton moves in a circular path perpendicular to a constant magnetic field. If the field strength of the magnet is increased, does the diameter of the circular path increase, decrease, or remain the same?
1 Answer
- Anonymous1 decade agoFavorite Answer
The diaameter will decrease. The centripetal force on the proton is F = qv X B (vector cross product). If B increases, F increases, so the proton has larger centripetal force, and therefore a smaller radius of travel.