math help please?

√12xy * √2xy^2= √24x^2 y^3= 2xy√6y

OK

√12xy * √2xy^2

√4*3xy *y√2x

2√3xy *y√2x

2xy√3y*√2

2xy√6y

= 2xy√6y

Hope that helps.

im not sure f this is the answer because of the way i'm lookin at it:

2xy 6y

the 6y is supposed to be in a radical and 2xy are whole numbers in front of the 6y

sorry if im wrong

sqrt(12xy)*sqrt(2xy^2)

(12xy)^(1/2) * (2xy^2)^(1/2)

[(12xy)*(2xy^2)]^(1/2)

[(24)*(x^2)*(y^3)]^(1/2)

[(4)*(6)*(x^2)*(y^3)]^(1/2)

2*x*y*[(6)*(y)]^(1/2)

2xy*sqrt(6y)

I don't know why they told you to assume x and y are positive... it doesn't matter if they are or not...

Maybe they're tryin to confuse you?

Multiply the inside of each radical: radical 24 x^2y^3

radical 4*6 X^2 Y^2Y^1

2xyradical 6y

all it is, is Square root 12XY times square root 2XY and then u have ur answer, that's it