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Babygurl91
Babygurl91 asked in Science & MathematicsMathematics · 1 decade ago

math help!?

How do I solve the quadratic equation by completing the square?! HELP!

x2 + 6x + 34 = 0

3 Answers

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  • norman
    Lv 7
    1 decade ago
    Favorite Answer

    x^2 + 6x + (3)^2 = -34 + 9

    (x+3)^2 = -25

    x+3 = +/-5i

    x = -3 +/- 5i

  • Sayee
    Lv 4
    1 decade ago

    x^2 + 6x + 34 = 0

    The trick here is, divide the co-efficient of x which is 6 by 2 so 6/2 = 3. Then you write - replace x^2 + 6x part with (x+3)^2

    (x+3)^2 + 34 - 9 = 0 ( -9 part comes from 3^2 = 9 meaning sqaure the previous answer you got and subtract it from the whole equation)

    Rest must be straightforward. This trick is helpful when dealing with larger numbers. Try some! It works!

    (x + 3)^2 = - 34 + 9

    (x + 3)^2 = -25

    x + 3 = -5i or x + 3 = 5i

    x = -3 - 5i or x = -3 + 5i

  • ben e
    Lv 7
    1 decade ago

    x^2 + 6x + 34 = 0

    x^2 + 6x = - 34

    x^2 + 6x + 9 = - 34 + 9

    (x + 3)^2 = -25

    x + 3 = -5i or x + 3 = 5i

    x = -3 - 5i or x = -3 + 5i

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