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One final question : Logarithms?
Solve for X. Give the EXACT value.
7^(2x+1) = 3
This is what I do :
(2x+1) Log 7 = log 3
2x+1 = log 3 / log 7
x = ( log 3 / 2 log 7 ) - 1
This is wrong, where am I messing up and whats the correct way? Thanks!
2 Answers
- MathematicaLv 71 decade agoFavorite Answer
You're fine to this point:
2x+1 = log 3 / log 7
Now, you have to subtract 1 from each side, so you have
2x = (log 3 / log 7) - 1
Now you divide both sides by 2. Here's where you have a problem.
x = [(log 3 / log 7) - 1] / 2
or
x = (log 3 / 2 log 7) - (1/2)
You forgot to divide the -1 by 2 at the end.
- Anonymous1 decade ago
7^(2x+1)=3
2x+1=log 3(base7)
=[log3-log7]
=[0.4771-0.8451]
=-0.3680.
2x=-1.3680
x=-0.6840.ANS.