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27^radical 5 x 9^ radical 5
I sort of know what to do but not sure. I know how to solve though.
7 Answers
- SivaLv 51 decade ago
27^radical 5 x 9^ radical 5
27^rt(5)*9^rt(5)
[27*9]^rt(5)
[{3}^3*{3}^2]^rt(5)
[{3}^5]^rt(5)
3
(x^a)^rt(a)=x
using this above only we get 3
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- PeterTLv 51 decade ago
27^(sqrt(5)) * 9^(sqrt(5))
27 = 3^3
9 = 3^2
27^(sqrt(5)) = (3^3)^(sqrt(5)) = 3^(3 sqrt(5))
9^(sqrt(5)) = (3^2)^(sqrt(5)) = 3^(2 sqrt(5))
27^(sqrt(5)) * 9^(sqrt(5)) = 3^(3 sqrt(5)) 3^(2 sqrt(5))
= 3^(3 sqrt(5) + 2 sqrt(5))
= 3^(5 sqrt(5))
- JLv 61 decade ago
27^(sqrt(5)) * 9^(sqrt(5))
27 = 3^3
9 = 3^2
27^(sqrt(5)) = (3^3)^(sqrt(5)) = 3^(3 sqrt(5))
9^(sqrt(5)) = (3^2)^(sqrt(5)) = 3^(2 sqrt(5))
- Anonymous5 years ago
-630