One Function Problem? Help?

This is really quite easy, but it only looks complicated. The problem is asking for what g of f of -2 is. f(-2) is a number. In the f(x) problem, plug -2 in.

-2^3 = -8

So f(-2) = -8. Substitute -8 for f(-2) in the original problem. Now the problem reads g(-8). Plug in -8 for x in the g(x) function.

g(-8) = 3(-8)

g(-8) = -24

g[f(-2)] = -24

I hope this helped.

The factors are all coordinates (x,y) area is the set of x values: {a million, 2, 3, 4, 5} selection is the set of y values: { -4, -3, -2, -a million, 0 } y = f(x} you will see that the corresponding y fee is -a million, the x fee is 4

g(f(x)) = 3(x^3)

g(f(-2) = 3(-2^3) = 3(-8) = -24

g[f(-2)] =3((-2)^3) = 3*-8 = -24

f(x) = x^3

g(x) = 3x

g[f(-2)] = 3*[(-2)^3]

= 3*-8

= -24

substitute the -2 into f(x).

then you got g(-8)

and the final answer is -24.

remember, always solve in the bracket first.

just a tip to be remembered. top is the 1st to be solved.

B-bracket

O-over

D-division

M-multiply

A-addition

S-subtraction

f(x) = x^3

g(x) = 3x

g(f(x)) = g(x^3) = 3x^3

So g(f(-2)) = 3.(-2)^3 = 3 x -8 = -24

f(-2) = (-2)^3=-8

g(x) = 3x

then

g[f(-2)] = g(-8) = 3*(-8)=-24

ok, i will give clues

* find f(-2) then put the result to the g(x) function

clear enup? gud luck ^^