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Algebra Help?

I am trying to "evaluate" the following expression.

5x + 3y = 30

There were no numbers to substitute the "x" and "y" variables. Wondering how to solve this question?

Update:

Basically, I am trying to find out what x and y is equal to. What times 5 + 3 time y will give me 30.. I have tried various Algebra tutorials online (math.com, etc.) and the only examples I can find are like the following: 6x + 6y = 70 where x and y are given variables. All then that's needed to be done is substitute. But I cannot seem to find any examples on how to solve for x and y with no substitutions... or variables given...

5 Answers

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  • cidyah
    Lv 7
    1 decade ago
    Favorite Answer

    As one of the answers says, you can only express y in terms of x. In order to solve for x and y, you'll need one more equation similar to what you have.

  • Anonymous
    1 decade ago

    You can graph a solution

    plug in a value for X to solve for Y.

    X|Y

    -----

    0|10

    RE: Additional Details

    9 minutes ago

    That's the thing, there are multiple (infinite) solutions, there is no single answer.

    X=0 and Y=10

    X=6 and Y=0

    These are both valid and true solutions. It's easy to convert these answers to points on a grid.

  • 1 decade ago

    5x+3y=30

    first solve for y,

    3y = 30 - 5x

    y= (30-5x)/3

    Now substitute this for the y in 5x+3y=30, you will get the value of x.

    now to solve for y, substitute the value of x u got from above.

  • 1 decade ago

    5x + 3y = 30

    rearranging

    3y = - 5x + 30

    y = -(5/3) + 10

    This is equation of a line with slope -5/3 and y- intercept of 10

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  • 1 decade ago

    Nothing to do here, unless there is more to the question

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