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I've a physics question posted below if someone could help me with it or answer it for me that'd be great..
As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t , and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g.
Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward).
From what height above the bottom of your window was the flower pot dropped?
Express your answer in terms of Lw,t , and g .
thanx for any help
2 Answers
- Anonymous1 decade agoFavorite Answer
HINT
The average speed while it passes your window is
v(ave) = Lw / t
and this occurs at time (1/2)t
So the average speed past the window is Lw / 2
- Anonymous1 decade ago
I would also need to know:
-The height of the viewer, relative to the window,
-The distance between the viewer and the window,
-The distance between the pot and the window
This is needed to determine the field of view, which is undoubtedly greater than Lw.