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Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Quadratic Formula Equation?

Could you please help my solve this equation using the quadratic formula. I know what the formula is, I just need help with doing this problem. thank you SO much!

t2 + 13t + 42 = 0.

PLEASE HELP! I can't figure this out.

Update:

I already plugged it in, I am having trouble once i get to the square root to find out what the answers are.

Update 2:

thank you so much i understand now!

9 Answers

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  • Bill F
    Lv 6
    1 decade ago
    Favorite Answer

    if you know the formula it is easy

    (-b + or - sqrt(b^2 - 4ac))/2a

    so for t^2 + 13t + 42 = 0

    a = 1

    b = 13

    c = 42

    and you just plug those in

    (-(13) + or - sqrt(13^2 - 4(1)(42))/2(1)

    (-13 + or - sqrt(169 - 168) / 2

    (-13 + or - sqrt(1)) /2

    (-13 + or - 1) /2

    t = (-13 + 1)/2 and t = (-13 -1)/2

    t = (-12)/2 and t = (-14)/2

    t = -6 and t = -7

    without doing the quadratic forumula you could have just tried to factor it.

    what two numbers multiply to 42 and add up to 13? 6 and 7

    (t+6)(t+7) = 0

    t + 6 = 0; t = -6

    t + 7 = 0; t = -7

  • 1 decade ago

    Quadratic formula is:

    [-b +/- sqrt(b^2 - 4ac)] / 2a

    Your equation: t2 + 13t + 42 = 0

    a = 1, b = 13, c = 42

    [-13 +/- sqrt(13^2 - 4 * 1 * 42)] / (2 * 1)

    [-13 +/- sqrt(169 - 168)] / 2

    [-13 +/- sqrt(1)] / 2

    [-13 +/- 1] / 2

    (-13 + 1) / 2 or (-13 - 1) / 2

    -12 / 2 or -14 / 2

    -6 or -7

  • 1 decade ago

    Delta = 13^2 - 4*42 = 169 - 168 = 1 = 1^2

    From there, the two roots are:

    t1 = (-13 - sqrt(Delta))/2 = (-14)/2 = -7

    t2 = (-13 + sqrt(Delta))/2 = -12/2 = -6

  • 1 decade ago

    t² + 13t + 42 = 0

    Forumla is:

    t = (-b ± √(b² - 4ac))/2a

    t = (-13 ± √(13² - 4(1)(42)))/2(1)

    t = (-13 ± √(169 - 168))/2

    t = (-13 ± √1)/2

    t = (-13 ± 1)/2

    t = (-13 + 1)/2 and (-13 - 1)/2

    t = (-12)/2 and (-14)/2

    t = -6 and -7

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  • 1 decade ago

    I think the formula is t^2 + 13t + 42

    so,

    (-b +- sqrt(b^2 - 4ac)) / 2a

    is

    (-13 +- sqrt(169 - 168)) / 2

    is

    (-13 +- 1) / 2

    is

    -14/2 = -7

    or

    -12/2 = -6

  • 1 decade ago

    t^2 + 13t + 42 = 0

    first calculate the delta:

    delta = b^2 - 4ac = 169 - 4*1*42 = 169 - 168 = 1

    root(delta) = 1

    then the roots are: x = (-b-root(delta))/2 or (-b+root(delta))/2

    therefore

    x= (-13-1)/2 or x= (-13+1)/2

    x=-7 or x=-6

    good luck to you in your future solutions! ;)

  • 1 decade ago

    t = [-13 +/- sqrt(13^2 -4(1)(42))]/(2*1)

    t = [-13 +/- sqrt(169 -168)]/2

    t = [-13 +/- 1]/2

    t = (-13 + 1)/2 = -6

    t = (-13 - 1)/2 = -7

  • 1 decade ago

    aha

    T^2 + 13T + 42 = 0

    first - get the factors for 42

    (1,42) (2,21) (3,14)(6,7)

    NOW - which set of factors, when added together, have a sum of 13 (since both 2nd and third parts are +)

    (t + ___) ( t + ____)

    u can fill in the blanks - all the best

  • 1 decade ago

    A = 1

    B = 13

    C = 42

    Just plug it into the formula

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