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bosh50
Lv 4
bosh50 asked in Science & MathematicsMathematics · 1 decade ago

factoring question 10 points?

why cant i factor x^2 - 4x + 5 by (x-5) (x+1)

i was told that this wasn't factorable and that i had to use the quadratic formula..Is this correct?

12 Answers

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  • 1 decade ago
    Favorite Answer

    Because -5 * 1 = -5, not +5

  • Anonymous
    1 decade ago

    Yes, the factors you have end up with a -5 at the end, not a +5. Have to use the quadratic formula.

  • 1 decade ago

    this is how to solve this problem:

    a=1

    b=-4

    c=5

    this is the formula for the quadratic formula:

    "-b" plus or minus the square root of "b^2 - 4ac".

    now u must substitute in the abc's into the formula:

    4 plus or minus the square root of 16 - 20.

    then u have to solve "16 - 20" which is "-4"

    then u will hav to square root the "-4"

    but here is the problem: u couldnt square root a negative number.

    so that law leaves u with no solution.

    so write this next to ur problem: No Solution

    hope this helped u out...even though it sounds confusing(srry about that)

  • Anonymous
    1 decade ago

    if you were to expand (x-5) (x+1), it would be x²-4x-5, because the -5 and +1 multiplied together become a -5

    that's why you have to use the quadratic formula

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  • 1 decade ago

    Your factoring produces x^2 - 4x - 5

    x^2 -4x +4 =-1

    (x-2)^2 = -1

    x-2 =i, x-2 = - i

    x=2+i, x= 2 -i

  • Anonymous
    1 decade ago

    because (x-5)(x+1) is x^2 +x -5x -5

    which is x^2 -4x -5 not the same problem

  • 1 decade ago

    No because when you FOIL it (first outside inside last) when you multiply the -5 by the +1, you get -5, not +5.

  • NNOSA
    Lv 5
    1 decade ago

    you just factored it you don't need the quadartic formula

  • Anonymous
    5 years ago

    I think you might be missing some information. For example: In the first one should there be a function (addition, multiplication, etc...) between the 2p and the 1, for the second one between the 2xy and the y^2?

  • ?
    Lv 7
    1 decade ago

    yes, it is not factorable over the reals

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