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factoring question 10 points?
why cant i factor x^2 - 4x + 5 by (x-5) (x+1)
i was told that this wasn't factorable and that i had to use the quadratic formula..Is this correct?
12 Answers
- Anonymous1 decade ago
Yes, the factors you have end up with a -5 at the end, not a +5. Have to use the quadratic formula.
- 1 decade ago
this is how to solve this problem:
a=1
b=-4
c=5
this is the formula for the quadratic formula:
"-b" plus or minus the square root of "b^2 - 4ac".
now u must substitute in the abc's into the formula:
4 plus or minus the square root of 16 - 20.
then u have to solve "16 - 20" which is "-4"
then u will hav to square root the "-4"
but here is the problem: u couldnt square root a negative number.
so that law leaves u with no solution.
so write this next to ur problem: No Solution
hope this helped u out...even though it sounds confusing(srry about that)
- Anonymous1 decade ago
if you were to expand (x-5) (x+1), it would be x²-4x-5, because the -5 and +1 multiplied together become a -5
that's why you have to use the quadratic formula
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- William BLv 71 decade ago
Your factoring produces x^2 - 4x - 5
x^2 -4x +4 =-1
(x-2)^2 = -1
x-2 =i, x-2 = - i
x=2+i, x= 2 -i
- Anonymous1 decade ago
because (x-5)(x+1) is x^2 +x -5x -5
which is x^2 -4x -5 not the same problem
- 1 decade ago
No because when you FOIL it (first outside inside last) when you multiply the -5 by the +1, you get -5, not +5.
- Anonymous5 years ago
I think you might be missing some information. For example: In the first one should there be a function (addition, multiplication, etc...) between the 2p and the 1, for the second one between the 2xy and the y^2?