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Woden501
Lv 6
Woden501 asked in Computers & InternetProgramming & Design · 1 decade ago

Is this adequate pseudocode for this program?

Here's the program's first part:

import java.util.Scanner;

import java.text.DecimalFormat;

public class FatGramCalculator

{

public static void main (String [] args)

{

DecimalFormat formatter = new DecimalFormat("#0.0");

Scanner keyboard = new Scanner (System.in);

// variable declarations

double calories; // number of calories

double fatGrams; // number of fat grams

double caloriesFromFat; // number of calories from fat

double percentageCaloriesFromFat; // percentage of calories from fat

// Get calories and fat grams from user

System.out.println("How many calories are there in the food item?");

calories = keyboard.nextDouble();

System.out.println(); // for empty line

System.out.println("How many grams of fat are there in the food item?");

fatGrams = keyboard.nextDouble();

System.out.println(); // for empty line

Update:

Here's the second:

// calculate the percentage of calories from fat

caloriesFromFat = fatGrams * 9;

if (caloriesFromFat > calories)

{

System.out.println("The amount of calories and/or fat grams you entered is invalid.");

}

else

{

percentageCaloriesFromFat = caloriesFromFat / calories;

System.out.println("The percentage of calories from fat in this item is " + formatter.format(percentageCaloriesFromFat * 100) + "%.");

if ( percentageCaloriesFromFat < .3 )

{

System.out.println("This item is low in fat");

}

}

}

}

Update 2:

Here's the pseudocode:

Have user enter the calories and the fat grams.

Calculate the caories from fat by multiplying the fat grans by 9.

If the calories from fat are more than the total calories then stop program and tell user.

If the calories from fat are less than the total calories then find the percentage of calories from fat by dividing the calories from fat by the total calories.

Output the percentage of calories from fat to the user.

If the percentage of calories from fat is less than 30% the output that the food is low in fat.

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