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help with my algebra hw???

The speed of a freight train is 14 km/h slower than the speed of a passenger train. The freight train travels 330 km in the same time that it takes the passenger train to travel 400 km. Find the speed of each train.

3 Answers

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  • 1 decade ago
    Favorite Answer

    First lay out your information.

    Train P travels 400 km at a speed of x km/h

    Train F travels 330 km at a speed of (x-14) km/h (because you are told that the freight train is 14 km/h slower) You always have to set your known variable as x and your unknown in terms of x.

    Next you set up a ratio:

    We'll put Train P on the left of the = and Train F on the right

    400 km = 330 km

    _______ _______

    x Km/h (x-14)km/h

    Solve the ratio by cross-multiplying:

    400 (x-14) = 330 x

    400x - 5600 = 330 x

    +5600 +5600

    400x = 330x + 5600

    - 330x -330x

    70x = 5600

    x = 80

    If x = 80, then x-14 = 66

    The passenger train is traveling at 80 km/h

    The freight train is traveling at 66 km/h

    Check by plugging your variables back into the original ratio and multiplying.

    Does 330 (x) = 400 (x-14)

    330 (80) = 400 (66)

    26,400 = 26,400

    It checks out !!

  • 1 decade ago

    P = speed of passenger train

    F = speed of freight train

    F = P - 14

    330/F = 400/P

    330/(P-14) = 400/P

    330P = 400(P-14) = 400P - 5600

    70P = 5600

    P = 80 km/h

  • Jenna
    Lv 4
    1 decade ago

    80 km/h

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