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help with my algebra hw???
The speed of a freight train is 14 km/h slower than the speed of a passenger train. The freight train travels 330 km in the same time that it takes the passenger train to travel 400 km. Find the speed of each train.
3 Answers
- carrie5260Lv 51 decade agoFavorite Answer
First lay out your information.
Train P travels 400 km at a speed of x km/h
Train F travels 330 km at a speed of (x-14) km/h (because you are told that the freight train is 14 km/h slower) You always have to set your known variable as x and your unknown in terms of x.
Next you set up a ratio:
We'll put Train P on the left of the = and Train F on the right
400 km = 330 km
_______ _______
x Km/h (x-14)km/h
Solve the ratio by cross-multiplying:
400 (x-14) = 330 x
400x - 5600 = 330 x
+5600 +5600
400x = 330x + 5600
- 330x -330x
70x = 5600
x = 80
If x = 80, then x-14 = 66
The passenger train is traveling at 80 km/h
The freight train is traveling at 66 km/h
Check by plugging your variables back into the original ratio and multiplying.
Does 330 (x) = 400 (x-14)
330 (80) = 400 (66)
26,400 = 26,400
It checks out !!
- Paschal HLv 61 decade ago
P = speed of passenger train
F = speed of freight train
F = P - 14
330/F = 400/P
330/(P-14) = 400/P
330P = 400(P-14) = 400P - 5600
70P = 5600
P = 80 km/h