Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
√[13+√2 + (7/3+√2)]?
all this is under the first radical sign...
and the end part is 7 divided by (3 +radical sign 2)
can anyone help?
2 Answers
- 1 decade agoFavorite Answer
set the whole thing equal to x and square both sides:
x^2=13+√2+(7/(3+√2))
want to get rid of the radical denominator so multiply this part:
(7/(3+√2))*((3-√2)/(3-√2))
this gives:
x^2=13+√2+(21-7√2)/(9-2)
x^2=13+√2+3-√2
x^2=16
x=4
follow that?
Source(s): algebra class - Ron WLv 71 decade ago
First, rationalize 7/(3+√2):
7/(3 + √2) = 7(3 - √2) / [(3 + √2)(3 - √2)]
= 7(3 - √2)/[3² - (√2)²]
= 7(3 - √2)/7
= 3 - √2
So
13 + √2 + [7/(3 + √2)] = 13 + √2 + 3 - √2 = 16
Thus,
√(13 + √2 + [7/(3 + √2)]) = √16 = 4
