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Jason C
Lv 4
Find the value of k if the lines y = 1/3x + 4 and kx - 2y + 1 = 0 are perpendicular.?
Please show work :)
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- shhrewdLv 61 decade agoFavorite Answer
1st line is y= 1/3 x + 4
Slope 1/3
2nd line must have slope -3
kx-2y+1=0
kx+1=2y
y= kx/2 + 1/2
k/2= -3
k= -6
- cidyahLv 71 decade ago
Slope of line 1 = 1/3
-2y=-kx-1
2y=kx+1
y=(k/2)x +1/2
slope of line 2 =k/2
If they are perpendicular, the product of their slopes is -1.
(1/3)(k/2)=-1
k=-6
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