Tryning to help my granddaughter with this, but don't know how. 4-8(-2-6t) t=-1 ? Please help! Thanks!?

4-8(-2-6t)

4-8(-2-6(-1))

4-8(-2+6)

4-8(4)

4-32

-28

4 - 8*(-2-6t)*t = -1

This will eventually take the form of a quadratic equation, which is

a*t^2 + b*t + c = 0

First step:

Add 1 to both sides to make the right side zero.

(4 - 8*(-2-6t)*t)+1 = (-1)+1

so now

5 - 8*(-2-6t)*t = 0

Second step:

Distribute the 8 and the t into the parentheses:

5 - (-2*8*t - 6t*8*t) = 0

so now,

5 + 16t + 48t^2 = 0

Third step:

Solve the quadratic equation, which is

48t^2+16t+5=0

there will be TWO answers for t, because there is a t^2 in the equation.

Use the Quadratic Formula to solve. The quadratic formula is:

t = (-b +/- sqrt(b^2 - 4ac))/(2a)

If you want to see this formula more clearly, go to

http://mathworld.wolfram.com/QuadraticFormula.html

hope that helps

You fill t in as -1 with parentheses( i am sorry i don't know how to spell that.) So you have

4-8[-2-6(-1)] You multiply -6 and -1 to get positive 6. 4-8(-2-6) -2-6 would be -8. 4-8 is -4. so then you have -4(-8)Then you just multiply to get positive 32.