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Derivadas. Calcule.?
a. CT = 34Q² + 875Q + 35
b. CT = 0,08Q³ + 875,45Q² + 43Q + 200
c. L = - 0,08Q² + 345Q
d. P = 430Q³ + 0,7Q² + 200
e. T = - 33S(à quinta potência) - 456s³ - 22
2 Answers
- Anonymous1 decade agoFavorite Answer
a) d CT = 64Q+875
b) d CT = 0,24Q² + 1750,9 Q+ 43
c) d L = -0,16Q+345
d) d P =1290Q²+0,14Q
e) d T = 165S4 (quarta potência) - 1368S²
- 1 decade ago
a) CT = 34Q² + 875Q + 35
CT'=(34Q²)' + (875Q)' + (35)'
CT'=68Q + 875 + 0
CT'=68Q + 875
b)CT= 0,08Q³ + 875,45Q² + 43Q + 200
CT'=(0,08Q³)' + (875,45Q²)' + (43Q)' + (200)'
CT'=0,24Q² + 1750,9Q + 43 + 0
CT'=0,24Q² + 1750,9Q+ 43
c)L= -0,08Q² + 345Q
L'=(-0,08Q²) + (345Q)'
L'= -0,24Q + 345
d)P= 430Q³ + 0,7Q² + 200
P'=(43Q³)' + (0,7Q²)' + (200)'
P'=1290Q² + 1,4Q + 0
P' =1290Q² + 1,4Q
e)T= - 33S(à quinta potencia) - 456S³ - 22
T'=(-33S à quinta)' - (456S³)' - (22)'
T'=-165S(à quarta potencia) - 1368S² -0
T'= -165S(à quarta potencia - 1368s²
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