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Derivadas. Ache o ponto máximo ou mínimo.?
a. CT = 34Q² + 875Q + 35
b. CT = - 875,45Q² + 43Q + 200
c. L = -0,08Q² + 345Q
d. P = 0,7Q² + 200
e. T = - 33S² - 456S - 22
2 Answers
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- KenshinLv 41 decade agoFavorite Answer
a) Derivada de CT:
68Q + 875
Igualando a zero para achar o ponto de mínimo.
68Q + 875 = 0
68Q = -875
Q = -12,87
Substitui na equação e acha o valor de CT.
- 1 decade ago
à MOLE
USE BÃSCARA
B² + OU - RAIZ DE B - 2AC / 2A
A) 85² +OU- RAIZ DE 875 - 2 X 34 X 35 / 2X 34
E ASSIM VAI SUBSTITUINDO
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