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A pendulum swings through than angles of 50 degrees each second. If the pendulum is 55 inches long......?
....how far does its tip move each second?
OR(IF U CAN PLS)
You have 276 feet of fencing to enclose a rectangular region. Find the dimensions of the rectangle that maximize the exclosed area?
a) 138 ft by 138 ft
b)138 ft by 34.5 ft
c) 71 ft by 67 ft
d) 69 ft by 69 ft
{how? and pls don't guess}
2 Answers
- DANIEL GLv 61 decade agoFavorite Answer
The distance 2*Pi*50/360*55=48 inches
d) The area of a square is always greater than the area of a rectangle whose perimeter is the same length.
- MΔgЇc ΞngΓLv 41 decade ago
Arc length = 2*(pi)*r* [(angle of arc to center of circle)/ 360]
Your angle to the center of the circle is 50 degrees. It makes this sweep in one second. If it went back and forth in one second, you would multiply your answer below by 2.
Your radius is the length of the pendulum.
Arc length = 2*pi*55*(50/360)
= 47.99 inches
The shape of a rectangular region that will give the maximum amount of area is also a square (provided that you are going to fence in all of the area, and not just 2 or 3 sides of it.)
You're given perimeter; calculate the length of one side of a square then, with all sides being equal:
276 / 4 =
x = 69
The area will be 69 x 69.