C Program code plzz fast!?

I don't like to produce a solution that will only work for one specific case, e.g. N = 10, so the code below will create a nice looking pyramid for the command-line-provided N up to 990. If you want to get into 4-digit numbers, just change the two instances of 4 in the code to 5 (or 6 for 5-digit numbers, etc.)

If this is for a class assignment, study and understand the code before using its techniques in your own solution. I'm sure you'll learn something.

#include <stdio.h>

int main(int argc, char *argv[]) {

int N,i,j,n,nSpace,h;

if ((argc < 2) || (sscanf(argv[1],"%d",&N) != 1)) {

printf("\nusage: %s <n>\n",argv[0]);

return -1;

}

for (i = 1, h = 1; i < N; i += ++h);

nSpace = h * 2;

for (j = 0, n = 1; j < h; j++, nSpace -= 2) {

for (i = 0; i < nSpace; i++) printf("%c",' ');

for (i = 0; i <= j; i++) printf("%4d",n++);

puts("");

}

return 0;

}

/* This is a fast simple program. (!i) is the same as saying (i==0). I'm sure it will need fixing to do what you want. C'mon try."/

#include <stdio.h>

int main()

{

int i, j;

for (i=0;i<4;i++)

{

for (j=0;j<10-(i+1);j++)

printf(" ");

if (!i) printf("1\n");

else if (i==1)printf("23\n");

else if (i==2)printf("456\n");

else printf("78910\n");

}

return 0;

}

basically google c++ and there are quite some academic web content. as far as studying the language is worried, It takes a lengthy time period and also you're able to continually study new issues. also dont assume it to be common, yet in case you recognize different languages its really a wide plus

#include "stdio.h"

#define N 10

main()

{

int i,j;

for(i=1; i<=N; i++)

{

for(j=1; j<=i; j++)

printf("*");

printf("\n");

}

printf("\n");

for(i=N; i>=1; i--)

{

for(j=i; j>=1; j--)

printf("*");

printf("\n");

}

printf("\n");

for(i=1; i<=N; i++)

{

for(j=i; j<N; j++)

printf(" ");

for(j=1; j<=i; j++)

printf("*");

printf("\n");

}

}