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factor 4r^2+9?
i cant remember how to factor like this =o
please help
4 Answers
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- Anonymous1 decade agoFavorite Answer
There is no solution in real numbers.
sqrt(-4ac)/2a
= sqrt(144)/8
=+/- 12i/8
= +/- 3i/2
So, (r - 3i/2)(r+3i/2) should work.
Where i is the square root of negative 1.
- Anonymous1 decade ago
4r^2+9=0
r^2 =-9/4
r= -2.25i (i.e. its an imaginary number because it comes from taking the square root of a negative).
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