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Another Algebra Problem?
The equation
A=(LP)/2-L^2
gives the area of a rectangle of perimeter P and length L. Suppose that you have 600 feet of fencing which you plan to use to fence in a rectangular area of land. Choose any two lengths for a rectangle and find the corresponding area for each using the given equation. Include units and show all calculations. Which of the two lengths that you chose gives a larger area? What is the corresponding width of each of the two rectangles?
1 Answer
- 1 decade agoFavorite Answer
length 1=200ft
A=(200x600)/2-200^2 = 60000-40000=20000 ft^2
width=20000/200=100ft
length2=250ft
A=(250x600)/2-250^2=75000-62500=12500 ft^2
width=12500/250=50ft
200ft length gives the larger area
