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how to find a point on arc if start point P1, End point P2 and its center C are given?
I have the following inputs.
1. Center of arc C = (xc, yc)
2. Start Point of arc P1 = (xs, ys)
3. End point of arc P2 = (xe,ye)
I need a point on the arc which can be on the bisecting line of points P1 & P2.
I need the simplified values of X & Y of the point in the arc.
1 Answer
- 1 decade agoFavorite Answer
first we find the average point between p1 & p2. it is xa=(xs+xe)/2 and ya=(ys+ye)/2.
then we should find the bisecting line of p1 and p2 which is :
y-ya=[ -(xs-xe)/(ys-ye) ] * (x-xa)
we shoul also find equation of arc which is:
(x-xc)^2 + (y-yc)^2 = [ (xs-xc)^2 + (ys-yc)^2 ]
(don't afraid from these equations , by substituting number they will simplify!! )
in the last step solve for interception point of these 2 equation.
this is exactly the point you want!
