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Factoring out imaginary numbers?
Ok, so I understand this:
x^2 + 4 = 0
x^2 = -4
x = (plus or minus) sqrt(-4)
x = (plus or minus) 2i
So, the question I'm having problems with is this:
x^2 + 2x +5 = 0
x^2 = -2x - 5
x = (plus or minus) sqrt(-2x-5)
Does it come out to this?:
x= sqrt(2x+t5), or x= sqrt(2x-5), or neither?
Thanks for any help.
2 Answers
- Anonymous1 decade agoFavorite Answer
You haven't solved the equation for x. For a quadratic like x^2 + 2x + 5 = 0, you should be using completing the square or the quadratic forumula.
- Anonymous5 years ago
This factors over the reals. x² + 20 would factor over the imaginaries. x² − 20 = (x + √20)(x − √20) = (x + 2√5)(x − 2√5)