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What is the mole fraction of an aqueous solution consisting of 7.175 mass % potassium permanganate?
Show work please and thank you.
Is it me or is there some info missing here? This is part of my online homework for Chem class, I would appreciate any help, thanks.
1 Answer
- SciMannLv 71 decade agoFavorite Answer
Let UNITs guide you; always USE THEM in your calculation to prevent errors
KMnO4 mole fraction = # moles of KMnO4 / (# moles of KMnO4 + # moles of water)
# moles of KMnO4 in 100g (any number of g will do as long as it is used for both calculations) = 0.07175 * 100 g soln / MW of KMnO4 in g/mole = ??
# moles of H2O in 100g = (100-0.07175) * 100 g soln / MW H2O in g/mole = ??
Plug and SOLVE
