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Chem homework question?

What is the solubility in mol/L of C2H6 at a partial pressure of 347.0 torr, if the solubility at a partial pressure of 523.9 torr is 1.241x10^-3 mol/L?

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  • Anonymous
    1 decade ago
    Favorite Answer

    S2/S1 = P2/P1

    ?/1.241x10^-3 mol/L = 347.0 torr/523.9 torr

    ? = 8.220 x 10^-4 mol/L

  • 1 decade ago

    try using this formula X1= n1/ E n1

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