Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
control system problem?
In a certain system an electric heating element was found to increase the temperature of a piece of metal 10 degrees for each ampere of current. The metal expands 0.001 in./deg and pushes on a load sensor that outputs 1v/0.005 in. of compression.
Is this how you setup?
10deg/1mA=
0.001in/deg/1mA=
1V/0.005in/1mA=
2 Answers
- 1 decade agoFavorite Answer
No, be careful. Your problem states 10 deg per Amp, not Milliamps (mA) as you are using to form your equation.
10 Degrees per Amp,
0.001" expansion per Degree.
So, 10 degrees = 0.01" expansion
The load sensor outputs 1V per 0.005" compression.
10 Degrees = 0.01" Expansion = 2V output Sensor output.
- Anonymous1 decade ago
Your question is vague.
From what I can tell your controller operates on current. The controller appears to be proportional with a gain of 10 degrees per ampere.
The output from the controller is a temperature. You have a plant model that says your metal expands 0.001 in/deg.
You have a sensor output that is a gain that converts this displacement into a voltage output.
You are missing a piece of information regarding how this voltage is used in the controller feedback. Maybe a gain that will convert a voltage to a current (i.e. resistance or something)? Or is this an open loop system? In which case you can just multiply all the gains together. If it is closed loop you have to consider the block diagram to properly account for the feedback.
