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just simple Division?

we know that every natural no. when divide by it self =1;

i.e 1/1=1

2/2=1

3/3=1

4/4=1

5/5=1

and so on.....

then why 0/0 not equal to 1 and is undefined.......

please solve this problem....

Update:

i know that 0 is not natural no.(and is a whole no.) but also the integers when divide by itself =1

i.e

-1/-1 =1

-2/-2 =1

and so on

9 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Because of what / means - a/b means how many times you can stack the number b into number a.

    But you can stack any amount of 0's into a 0 and it will still hold. 0/0=0 is correct. 0/0=1 is correct. 0/0=5 is correct. 0/0=infinity is correct. Hence, undefined.

  • 1 decade ago

    Multiplication and division are inverse operations...

    so if 10/2 = 5, that means that 5 * 2 = 10

    0 / 2 = 0 means that 0 * 2 = 0

    if 0 / 0 = 1, then 1 * 0 = 0 (seems okay so far)

    but 0 / 0 could also = 2, or 3, or 1,000,000,001, or -55.8, or pi, or....

    this is clearly not acceptable in math, and we disallow division by 0 as an undefined operation (or the indeterminate case if we're talking about limits-- because it can take on other values then)

    ...And... if the numerator is anything other than 0, that means that if 5 / 0 = x, that x * 0 = 5, meaning that x = ?

  • 1 decade ago

    Abstract algebra

    Any number system which forms a commutative ring, as do the integers, the real numbers, and the complex numbers, for instance, can be extended to a wheel in which division by zero is always possible, but division has then a slightly different meaning.

    The concepts applied to standard arithmetic are similar to those in more general algebraic structures, such as rings and fields. In a field, every nonzero element is invertible under multiplication, so as above, division poses problems only when attempting to divide by zero. This is likewise true in a skew field (which for this reason is called a division ring). However, in other rings, division by nonzero elements may also pose problems. For example, the ring Z/6Z of integers mod 6. The meaning of the expression should be the solution x of the equation 2x = 2. But in the ring Z/6Z, 2 is not invertible under multiplication. This equation has two distinct solutions, x = 1 and x = 4, so the expression is undefined.

    In field theory, the expression is only shorthand for the formal expression ab − 1, where b − 1 is the multiplicative inverse of b. Since the field axioms only guarantee the existence of such inverses for nonzero elements, this expression has no meaning when b is zero. In modern texts the axiom is included in order to avoid having to consider the one-element field where the multiplicative identity coincides with the additive identity. In such 'fields' however, 0 = 1, and , and division by zero is actually noncontradictory.

    Source(s): wiki
  • 1 decade ago

    because there is nothing....the other numbers such as 1 divided by it self equals one as a whole...if you have nothing to begin with( having 0 be the denominater) how then would you have 1...or it as a whole..you get what im saying? there is nothing for you to divide. 5 pieces of five pieces gives you the WHOLE piece...0 pieces of nothing give you nothing. =].......about being undefined is just saying that 0 into 0 is indefinate because there is no stop to how many times 0 can be stacked into 0

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  • Anonymous
    1 decade ago

    because it's a rule that any number that is divided by 0 is undefined

  • Anonymous
    1 decade ago

    Because 0 is neutral!

  • 1 decade ago

    try to distribute 100 apples to Zero people

    also in case of integers...first the negative signs gets cancelled off. thats why you get 1

  • 1 decade ago

    because u thinks wrong anything dividedby 0 is always gives u an unidentified no.

  • Anonymous
    1 decade ago

    because 0 hasn't got any value

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