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How do i calculated ∆G for ATP hydrolysis...?

if [ATP]= 2x10^-3 M, [ADP]= 10^-4 M and [Pi]=10^-2 M

the ∆G^o’ for the hydrolysis of ATP is -37.9jK/mol

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  • Larkin
    Lv 5
    1 decade ago
    Favorite Answer

    Use the equation ∆G = ∆G^o + RTlnQ

    Using the equation for ATP hydrolysis and the concentrations given you can work out Q.

    ATP --> ADP + Pi

    Q = [ADP][Pi] / [ATP]

    Q = (10^-4 x 10^-2) / 2x10^-3

    Q = 0.0005

    Then substitute this value into the equation ∆G = ∆G^o + RTlnQ, along with R (8.314 J/mol K), T (assuming a temperature of 25C, which is equal to 298K) and the value of ∆G^o that you were given (converted to J/mol).

    ∆G = -37900J/mol + (8.314J/mol K x 298K x ln0.0005)

    ∆G = -37900J/mol + -18832J/mol

    ∆G = -56732J/mol

    ∆G = -56.7kJ/mol

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