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What is the limit for this function?
lim (sin (ax))/x
x -> 0
3 Answers
- 1 decade agoFavorite Answer
lim as x goes to zero of (sinx)/x =1
lim as x goes to zero of (sinax)/ax =1
so:
lim as x goes to zero of (sinax)/x =
lim as x goes to zero of a((sinax)/ax )=
a(lim as x goes to zero of ((sinax)/ax ))= (a)(1) = a
- 1 decade ago
sin(0)/0 can't exist.
Use L'Hospital's Rule, which is use find the derivative of the top and bottom separately, so it'd look like
(cos(ax)*a)/1, so as that approaches zero cos(0) = 1*a = a/1 = a.
The limit of that function is 'a'.
- Anonymous1 decade ago
the limit doesn't exist!!!
haha, i wouldn't know...
