Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Calculus Continuity question?

If f is continuous and 0 <= f(x) <= 1 for x belongs to [0, 1], then prove that there exists c in [0, 1] such that f(c) = c.

1 Answer

Relevance
  • Awms A
    Lv 7
    1 decade ago
    Favorite Answer

    If f(0) = 0 or f(1) = 1, then we have our c already, so we might as well assume that f(0) > 0 and f(1) < 1.

    Now consider g(x) = f(x) - x.

    g is continuous, g(0) = f(0) - 0 > 0, and g(1) = f(1) - 1 < 0.

    Thus by the intermediate value theorem, there's a c in (0,1) such that g(c) = 0.

    In other words, f(c) - c = 0, from which we get

    f(c) = c.

Still have questions? Get your answers by asking now.