Fake SAT practice question?

the correct answer is D.

if you try to plug in (-1) and (1) for x you will see that the y value is zero just like the graphs shows you so.

here's college boards explanation

Here's Why:

The function with equation y = (–x)2 + 1 and the function with equation y = |x2 + 1| each have a minimum value of 1 when x = 0, but the function graphed does not have a minimum value of 1, so these options cannot be correct. The graph of the function with equation y = –x2 + 1 contains the point (2, –3), but the function graphed does not contain any points with negative y-coordinates, so this option cannot be correct. The graph of the function with equation y = |(x – 1)2| is not symmetric with respect to the y-axis, so it cannot be the equation of the function graphed. Therefore, the only equation that could correspond to the function graphed is y = |x2 – 1|. Its graph is the absolute value of a parabola opening upward with vertex at (0, –1).

Difficulty: Hard

Question Type: Standard Multiple Choice

(Mathematics)

Its D

it has to be an absolute value function because it reflects over the y axis

it has to be x^2-1 cos its a parabola with vertex -1

very hard question, but I would guess B

its D