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Electrician problem: An electrician, a carpenter, and a plumber are hired to work on a house. The electrician ?
earns $24 per hour, the carpenter earns $21.50 per hour, and the plumber earns $25 per hour. The first day on the job, they worked a total of 18 hours and earned a total of $425. The carpenter worked 2 more hours than the electrician did. Find the number of hours that each of these people worked the first day. Define a variable or variables, write an equation or system of equations, solve, then answer in words.
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3 Answers
- G BLv 41 decade agoFavorite Answer
Let x, y, and z represent number of hrs the electrician, carpenter and plumber worked, respectively.
24x+21.5y+25z=425
x+y+z=18
x-y=-2 (the carpenter,y, worked 2 more hrs than the electrician, x. So, x-y=-2)
Set up a matrix and use your calculator or the Gauss-Jordan elimination method. I opt for the calculator.
24...21.5...25...425
1.....1........1.....18
1......-1......0......-2
This matrix can be used to find the solution.
in row-reduced form you have:
1.....0......0.....4
0.....1......0.....6
0.....0......1.....8
So, x=4,y=6 and z=8
or, Electrician worked 4 hrs
Carpenter worked 6 hrs
Plumber worked 8 hrs
- William BLv 71 decade ago
x= electrician hours
x+2= carpenter hours
18-(x+x+2) =16-2x=plumber hours
24x +21.5(x+2) + 25(16-2x) =425
24x +21.5x +43 +400 -50x =425
-4.5x = -18
x= 4 electrician hours
x+2=6 carpenter hours
8 plumber hours