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What are two consecutive odd integers, such that seven times the smaller minus three times the larger in 86.?
Help I need this for extra credit. For all you mathmaticians this should be easy. This is eighth grade math!!!!!!!!!!!!!! Thank you
PPPPPPPPPPLZZZZZZZZ I NEED THIS BY TOMMORROW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
2 Answers
- Anonymous1 decade agoFavorite Answer
23 x7 = 161
25 x 3 =75
161 - 75 =86
The consecutive odd integers are 23 and 25
- duenwaldLv 44 years ago
enable us to call the "smallest" integer "n". So the three consecutive integers are: n, n+a million, n+2 From what you have advised: 3(n+2) = n + n + a million + 40 seven 3n + 6 = 2n + 40 8 consequently n = 40 two the three integers are consequently: 40 two, 40 3, 40 4
