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I am trying to help my daughter with her Algebra... PLEASE HELP?
Please don't give us the answer if you know it, but please give us an idea of how to set this problem up.
We sold gift wrap. $4 for solid $6 for print. Total rolls sold was 480
we collected $2340. How many rolls of each kind of gift wrap were sold?
Thanks,
8 Answers
- Pi R SquaredLv 71 decade agoFavorite Answer
Hi,
S = # of solid
P = # of print
S + P = 480
4S + 6P = 2340
Multiply the first equation by -4 and add the equations to solve.
-4(S + P = 480)
4S + 6P = 2340
-4S - 4P = -1920
4S + 6P = 2340
------------------------
2P = 420
P = 210
If P = 210 and S + P = 480, then S = 270
270 rolls of solid and 210 rolls of print <==ANSWER
I hope that helps!! :-)
- Jeff ALv 41 decade ago
Okay first you have to set up some equations that are hidden in the word problem:
$4 for each roll of solid gift wrap
we can define x to be the number of solid gift wrap rolls sold
$6 for each roll of printed gift wrap
we can define 480 - x to be the number of of printed rolls of gift wrap sold since 480 rolls were sold altogther, and if x of them were solid, the rest must be printed.
that gives us the equation
4x+6(480-x) = 2340 since 2340 is the total cost of money brought in by selling wrapping paper
no we can simplify to get:
4x+6*480-6x = 2340
6*480-2x=2340
and just continue to solve for x. After you solve for x make sure you look at the question again to see if you answered it, always do this! So in this problem they don't care what x is, after all we made that up. They want to know how much of each type of wrapping paper was sold, so x was how much solid was sold and 480-x was how many printed rolls were sold.
good luck!
- Anonymous1 decade ago
let a be the number of $4 rolls, and b be the number of $6 rolls
a + b = 480--> the # of 4 dollar rolls plus the # of 6 dollar rolls = 480
4a+6b = 2340 --> the total cost of the rolls is $2340
rearrange the first equation a + b = 480 to a = 480 -b
substitute a = 480 -b into 4a+6b = 2340
4a+6b = 2340
4(480 - b) + 6b = 2340
1920 - 4b + 6b = 2340
2b = 2340 - 1920
2b = 420
b = 420/2 = 210
substitute b= 210 into any equation above, the most easy one to do would be a = 480 -b
a = 480 -b
a = 480 - 210
a = 270
so there are 270 $4 rolls, and 210 $6 rolls
Source(s): grade 11 student - airjarrodLv 71 decade ago
Let x = the number of solid
Let y = the number of print
If you sold 480, then x + y = 480. (Solids + Print)
If the solid cost $4 and the print $6, then solid part of the money would be expressed as 4x ($4 times the number you sold, x)
Same for the print ones, that's 6y. So if you add the money together, 4x + 6y = 2340.
Solve for one variable or the other.
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- 1 decade ago
First let solid rolls = x and print =y
then from there you get two equations
4x + 6y = 2340
x + y = 480
from there you can solve for x (or y) then when you find x plug your answer into the second equation where you will find y.
- Anonymous1 decade ago
System of equations:
4s + 6p = 2340
s + p = 480
s stands for solid
p stands for print
(Trust you know how to solve it)
- 1 decade ago
you can use a system to answer this.
x+y=480
4x+6y=2340
multiply the top by -4 to eliminate the x's so you have
-4x-4y= -1920
4x+6y=2340
so you add those two and you get
2y=420
divide by 2 and y=210
then substitute back in one of the equations, i.e.
x+210=480 so x=270
- Anonymous1 decade ago
use a system of equations
4x + 6y=2340
x + y = 480
Source(s): I'm in pre-ap precalculus