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could someone explain to me how to find the margin of error (statistics class)?

Update:

for a list of body temperatures we have n=106

x bar=98.20

s=.62. using a 95% degree of confidence, find both the margin of error E and the confidence interval for mu

3 Answers

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  • gab BB
    Lv 6
    1 decade ago
    Favorite Answer

    According to the central limit theorem, since our sample size of n=106 is large(the thumb of the rule is at least greater than 30), then the sampling distribution of all possible sample means of body temperatures-x-bar will follow the z normal distribution.

    Our confidence level = 95%

    100(1-alpha)% = 95%

    1-alpha = 0.95

    alpha = 0.05

    The margin of error E

    = The error Bound,B

    = z(alpha/2)*(s/√n)

    = z(0.05/2)*(0.62/√106)

    = z0.025*(0.62/√106)

    = 1.96*(0.62/√106)

    A 95% confidence interval for the true(population) mean of body temperatures

    = [x-bar (+-) z(alpha/2)*(s/√n)]

    = [98.20 (+-)1.96*(0.62/√106)]

    = [98.08,98.32]

    Hope this helps.

  • ?
    Lv 4
    4 years ago

    Your null could could be equivalent to $25. Then if that happens so infrequently, we are in a position to assume they the two spend greater, much less or no longer equivalent to $25. you opt for something to attempt against. it is your issue. Do they spend $25 in Kingfield and $40 9 at Westline? Suggesting something at Westline makes human beings spend greater? The formula for findign the pattern length is Z* (inverse of ninety 5%) circumstances inhabitants SD / margin of errors needed. for this reason you opt for 0.5 of what you have so (Z*x?/3.01)^2 = N. this is (2.576X32.988/3.07)^2= 766 contributors are needed to get a margin of errors 0.5 of what you have now. once you run the two pattern Z try you will understand the P fee. it is the possibility that the outcomes ensue via twist of destiny. If it happens via twist of destiny eighty% of the time (p=0.20) then there isn't any distinction between the two shops. If It happens ninety 5% of the time the way i presumed it may (p=0.05) then i understand something is going on at Westline that's no longer going on at Kingfield. and that's all you're allowed to declare approximately it. there's a statistically significant distinction. you could't say what the version is.

  • 1 decade ago

    There are quite a few ways to display the margin of error; can you post the question in complete please?

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