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please help me solveeeeeeeeeeeeeeeee this?
-3(x^2+y^2)+x^2=? x=2 y=-3
please show me steps plus answer?
6 Answers
- Doc EnglishLv 41 decade agoFavorite Answer
You have everything here, there only one unknown which we'll call z; so ...
z = -3 x (2^2 + 3^2) + 2^2
z= -3 x (4 + 9) + 4
z = (-3 x 13) + 4
z = -39 + 4
z = -35
- 1 decade ago
Substitute for x and y
then follow the order of operations
-3(2^2 +(-3)^2) + 2^2
Do the parentheses first
-3(4 + 9) + 2^2
-3(13) + 2^2
Do exponents next
-3(13) + 4
Then multiply
-39 + 4
Then add
-35
- Anonymous1 decade ago
-3 (x^2 + y^2) + x^2 =?
-3 (2^2 + (-3)^2) + 2^2 =?
-3 (4 + (-3) (-3))+ 4 =?
-3 (4 + 9) +4 =?
-3 (13) + 4 =?
-39 + 4 = ?
-35 =?
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- Anonymous1 decade ago
2^2=4
3^2=9
so...
-3(4+9)+4
4+9=13
13 x -3= -39
-39+4= -35
So...
-35 is your answer