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Help MATH problem distance problem?
Instead pf riding a tricycle, Milda walks from her house to school after she learned that walking is good for the health. If the time in walking the distance from the house to school at 4kph is 30 minutes longer than what is required at 5kph when taking a tricycle, find its distance.
4 Answers
- 5 years ago
assuming it sails 120km in t hours to grand banks . so V = 120 / t in the return trip : its speed is V - 10 , and time = t + 2 so V - 10 = 120 / (t + 2) so 120/t - 10 = 120 / (t + 2) => 120/t - 120/(t+2) = 10 divide by 10 : => 12/t - 12/(t+2) = 1 mult by t(t+2) u ge : 12(t+2) - 12t = t(t+2) => 12t + 24 - 12t = t^2 + 2t so t^2 + 2t - 24 = 0 => (t + 6)(t - 4) = 0 => t = 4h , hence V = 120/4 = 30 km/h
- Anonymous1 decade ago
using s = d/t formula
on tricyle: 5=d/t
by walking: 4=d/(t+30)
from the first equation, making t the subject, t= d/5
and then you substitute that into the next formula
4= d/(d/5+30)
cross multiply and get the answer
d/5= 120
d=600
